Base | Representation |
---|---|
bin | 100100011111011011111… |
… | …1100111111001101100101 |
3 | 122202110101210022210102102 |
4 | 1020332313330333031211 |
5 | 1124132330120140032 |
6 | 14400000352221445 |
7 | 1025226063363125 |
oct | 110766774771545 |
9 | 18673353283372 |
10 | 5015313052517 |
11 | 1663a89518569 |
12 | 69000223a885 |
13 | 2a4c3272b1a1 |
14 | 134a573bac85 |
15 | 8a6d6c72362 |
hex | 48fb7f3f365 |
5015313052517 has 2 divisors, whose sum is σ = 5015313052518. Its totient is φ = 5015313052516.
The previous prime is 5015313052493. The next prime is 5015313052553. The reversal of 5015313052517 is 7152503135105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3117534047716 + 1897779004801 = 1765654^2 + 1377599^2 .
It is a cyclic number.
It is not a de Polignac number, because 5015313052517 - 218 = 5015312790373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5015303052517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507656526258 + 2507656526259.
It is an arithmetic number, because the mean of its divisors is an integer number (2507656526259).
Almost surely, 25015313052517 is an apocalyptic number.
It is an amenable number.
5015313052517 is a deficient number, since it is larger than the sum of its proper divisors (1).
5015313052517 is an equidigital number, since it uses as much as digits as its factorization.
5015313052517 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78750, while the sum is 38.
The spelling of 5015313052517 in words is "five trillion, fifteen billion, three hundred thirteen million, fifty-two thousand, five hundred seventeen".
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