Base | Representation |
---|---|
bin | 100100100010001000110… |
… | …1111000111010010110101 |
3 | 122210000101002110100021010 |
4 | 1021010101233013102311 |
5 | 1124231220232113331 |
6 | 14402400145542433 |
7 | 1025522615424312 |
oct | 111042157072265 |
9 | 18700332410233 |
10 | 5021114332341 |
11 | 166649615a9a8 |
12 | 691161044a19 |
13 | 2a564859a343 |
14 | 135047a5bd09 |
15 | 8a926204e46 |
hex | 49111bc74b5 |
5021114332341 has 64 divisors (see below), whose sum is σ = 7015886150400. Its totient is φ = 3190213361664.
The previous prime is 5021114332303. The next prime is 5021114332361. The reversal of 5021114332341 is 1432334111205.
It is not a de Polignac number, because 5021114332341 - 221 = 5021112235189 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5021114332299 and 5021114332308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5021114332301) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2268916351 + ... + 2268918563.
It is an arithmetic number, because the mean of its divisors is an integer number (109623221100).
Almost surely, 25021114332341 is an apocalyptic number.
It is an amenable number.
5021114332341 is a deficient number, since it is larger than the sum of its proper divisors (1994771818059).
5021114332341 is a wasteful number, since it uses less digits than its factorization.
5021114332341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3430.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 5021114332341 its reverse (1432334111205), we get a palindrome (6453448443546).
The spelling of 5021114332341 in words is "five trillion, twenty-one billion, one hundred fourteen million, three hundred thirty-two thousand, three hundred forty-one".
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