Base | Representation |
---|---|
bin | 100100100010010010000… |
… | …0110011101001110000111 |
3 | 122210001011120012220100221 |
4 | 1021010210012131032013 |
5 | 1124232333121110401 |
6 | 14402450513445211 |
7 | 1025533346336311 |
oct | 111044406351607 |
9 | 18701146186327 |
10 | 5021422441351 |
11 | 1666634072848 |
12 | 691228270807 |
13 | 2a5697377074 |
14 | 1350769427b1 |
15 | 8a9432b67a1 |
hex | 4912419d387 |
5021422441351 has 2 divisors, whose sum is σ = 5021422441352. Its totient is φ = 5021422441350.
The previous prime is 5021422441303. The next prime is 5021422441411. The reversal of 5021422441351 is 1531442241205.
5021422441351 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5021422441351 - 27 = 5021422441223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5021422741351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2510711220675 + 2510711220676.
It is an arithmetic number, because the mean of its divisors is an integer number (2510711220676).
Almost surely, 25021422441351 is an apocalyptic number.
5021422441351 is a deficient number, since it is larger than the sum of its proper divisors (1).
5021422441351 is an equidigital number, since it uses as much as digits as its factorization.
5021422441351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38400, while the sum is 34.
Adding to 5021422441351 its reverse (1531442241205), we get a palindrome (6552864682556).
The spelling of 5021422441351 in words is "five trillion, twenty-one billion, four hundred twenty-two million, four hundred forty-one thousand, three hundred fifty-one".
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