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502312101213253 is a prime number
BaseRepresentation
bin111001000110110011010011…
…0010110111111010001000101
32102212112120022222220211222011
41302031212212112333101011
51011314340140402311003
64540154554342534221
7210542565064126402
oct16215464626772105
92385476288824864
10502312101213253
11136063402981541
124840754a437371
1318738a9bb68276
148c0806d2952a9
153d1145564e46d
hex1c8d9a65bf445

502312101213253 has 2 divisors, whose sum is σ = 502312101213254. Its totient is φ = 502312101213252.

The previous prime is 502312101213173. The next prime is 502312101213359. The reversal of 502312101213253 is 352312101213205.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 281059625517889 + 221252475695364 = 16764833^2 + 14874558^2 .

It is a cyclic number.

It is not a de Polignac number, because 502312101213253 - 221 = 502312099116101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (502312101213953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251156050606626 + 251156050606627.

It is an arithmetic number, because the mean of its divisors is an integer number (251156050606627).

Almost surely, 2502312101213253 is an apocalyptic number.

It is an amenable number.

502312101213253 is a deficient number, since it is larger than the sum of its proper divisors (1).

502312101213253 is an equidigital number, since it uses as much as digits as its factorization.

502312101213253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 502312101213253 its reverse (352312101213205), we get a palindrome (854624202426458).

The spelling of 502312101213253 in words is "five hundred two trillion, three hundred twelve billion, one hundred one million, two hundred thirteen thousand, two hundred fifty-three".