Base | Representation |
---|---|
bin | 1001010111010000… |
… | …01110001010001101 |
3 | 110222100001120102021 |
4 | 10223220032022031 |
5 | 40243343300331 |
6 | 2150452330141 |
7 | 235400132335 |
oct | 45350161215 |
9 | 13870046367 |
10 | 5026931341 |
11 | 214a631a13 |
12 | b83613951 |
13 | 6215cabb3 |
14 | 3598b20c5 |
15 | 1e64c6211 |
hex | 12ba0e28d |
5026931341 has 2 divisors, whose sum is σ = 5026931342. Its totient is φ = 5026931340.
The previous prime is 5026931317. The next prime is 5026931353. The reversal of 5026931341 is 1431396205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4946308900 + 80622441 = 70330^2 + 8979^2 .
It is a cyclic number.
It is not a de Polignac number, because 5026931341 - 211 = 5026929293 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5026931297 and 5026931306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5026931381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2513465670 + 2513465671.
It is an arithmetic number, because the mean of its divisors is an integer number (2513465671).
Almost surely, 25026931341 is an apocalyptic number.
It is an amenable number.
5026931341 is a deficient number, since it is larger than the sum of its proper divisors (1).
5026931341 is an equidigital number, since it uses as much as digits as its factorization.
5026931341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 34.
The square root of 5026931341 is about 70900.8557141590. The cubic root of 5026931341 is about 1713.0405806197.
The spelling of 5026931341 in words is "five billion, twenty-six million, nine hundred thirty-one thousand, three hundred forty-one".
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