Base | Representation |
---|---|
bin | 100100100110111100011… |
… | …0110110100101110110101 |
3 | 122211000000022101010011012 |
4 | 1021031320312310232311 |
5 | 1124413334142410201 |
6 | 14411224203322005 |
7 | 1026336430153064 |
oct | 111157066645665 |
9 | 18730008333135 |
10 | 5031434341301 |
11 | 166a901575425 |
12 | 693161220305 |
13 | 2a660166cb14 |
14 | 1357464c21db |
15 | 8ad2c2255bb |
hex | 49378db4bb5 |
5031434341301 has 2 divisors, whose sum is σ = 5031434341302. Its totient is φ = 5031434341300.
The previous prime is 5031434341279. The next prime is 5031434341309. The reversal of 5031434341301 is 1031434341305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2795216172100 + 2236218169201 = 1671890^2 + 1495399^2 .
It is a cyclic number.
It is not a de Polignac number, because 5031434341301 - 230 = 5030360599477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5031434341309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2515717170650 + 2515717170651.
It is an arithmetic number, because the mean of its divisors is an integer number (2515717170651).
Almost surely, 25031434341301 is an apocalyptic number.
It is an amenable number.
5031434341301 is a deficient number, since it is larger than the sum of its proper divisors (1).
5031434341301 is an equidigital number, since it uses as much as digits as its factorization.
5031434341301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 5031434341301 its reverse (1031434341305), we get a palindrome (6062868682606).
It can be divided in two parts, 5031434 and 341301, that added together give a palindrome (5372735).
The spelling of 5031434341301 in words is "five trillion, thirty-one billion, four hundred thirty-four million, three hundred forty-one thousand, three hundred one".
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