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50321312061301 is a prime number
BaseRepresentation
bin10110111000100010101111…
…11011100001011101110101
320121011200002202111011212201
423130101113323201131311
523043431021341430201
6255005142553544501
713412411011034131
oct1334212773413565
9217150082434781
1050321312061301
111504116a86a496
125788735715131
1322103829c8338
14c5d7c8db23c1
155c3e8d35d801
hex2dc457ee1775

50321312061301 has 2 divisors, whose sum is σ = 50321312061302. Its totient is φ = 50321312061300.

The previous prime is 50321312061247. The next prime is 50321312061311. The reversal of 50321312061301 is 10316021312305.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50315628409201 + 5683652100 = 7093351^2 + 75390^2 .

It is a cyclic number.

It is not a de Polignac number, because 50321312061301 - 213 = 50321312053109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50321312061301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50321312061311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25160656030650 + 25160656030651.

It is an arithmetic number, because the mean of its divisors is an integer number (25160656030651).

Almost surely, 250321312061301 is an apocalyptic number.

It is an amenable number.

50321312061301 is a deficient number, since it is larger than the sum of its proper divisors (1).

50321312061301 is an equidigital number, since it uses as much as digits as its factorization.

50321312061301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 28.

Adding to 50321312061301 its reverse (10316021312305), we get a palindrome (60637333373606).

The spelling of 50321312061301 in words is "fifty trillion, three hundred twenty-one billion, three hundred twelve million, sixty-one thousand, three hundred one".