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50321644612331 is a prime number
BaseRepresentation
bin10110111000100011010111…
…10000000110101011101011
320121011200221221020112010112
423130101223300012223223
523043432212010043311
6255005235553404535
713412422156465511
oct1334215360065353
9217150857215115
1050321644612331
1115041320556a54
125788808b6974b
1322104068822b1
14c5d81b21a4b1
155c3eac64c28b
hex2dc46bc06aeb

50321644612331 has 2 divisors, whose sum is σ = 50321644612332. Its totient is φ = 50321644612330.

The previous prime is 50321644612177. The next prime is 50321644612333. The reversal of 50321644612331 is 13321644612305.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 50321644612331 - 238 = 50046766705387 is a prime.

It is a super-2 number, since 2×503216446123312 (a number of 28 digits) contains 22 as substring.

Together with 50321644612333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (50321644612333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25160822306165 + 25160822306166.

It is an arithmetic number, because the mean of its divisors is an integer number (25160822306166).

Almost surely, 250321644612331 is an apocalyptic number.

50321644612331 is a deficient number, since it is larger than the sum of its proper divisors (1).

50321644612331 is an equidigital number, since it uses as much as digits as its factorization.

50321644612331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 50321644612331 in words is "fifty trillion, three hundred twenty-one billion, six hundred forty-four million, six hundred twelve thousand, three hundred thirty-one".