Base | Representation |
---|---|
bin | 1110101001011001010… |
… | …01110011110010000101 |
3 | 1210010000002002200202202 |
4 | 13110230221303302011 |
5 | 31221134121044031 |
6 | 1023110011244245 |
7 | 51234155143061 |
oct | 7245451636205 |
9 | 1703002080682 |
10 | 503260331141 |
11 | 184482378547 |
12 | 81650a49685 |
13 | 385c37511b9 |
14 | 1a502234aa1 |
15 | d156e9c2cb |
hex | 752ca73c85 |
503260331141 has 2 divisors, whose sum is σ = 503260331142. Its totient is φ = 503260331140.
The previous prime is 503260331117. The next prime is 503260331159. The reversal of 503260331141 is 141133062305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 302999606116 + 200260725025 = 550454^2 + 447505^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-503260331141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (503260331111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251630165570 + 251630165571.
It is an arithmetic number, because the mean of its divisors is an integer number (251630165571).
Almost surely, 2503260331141 is an apocalyptic number.
It is an amenable number.
503260331141 is a deficient number, since it is larger than the sum of its proper divisors (1).
503260331141 is an equidigital number, since it uses as much as digits as its factorization.
503260331141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 503260331141 its reverse (141133062305), we get a palindrome (644393393446).
The spelling of 503260331141 in words is "five hundred three billion, two hundred sixty million, three hundred thirty-one thousand, one hundred forty-one".
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