Base | Representation |
---|---|
bin | 10110111001000001111101… |
… | …01010100111010010010101 |
3 | 20121020021100111212111012001 |
4 | 23130200332222213102111 |
5 | 23044214330411124402 |
6 | 255020553401155301 |
7 | 13413543152530111 |
oct | 1334407652472225 |
9 | 217207314774161 |
10 | 50338068067477 |
11 | 15048289127983 |
12 | 578ba3118bb31 |
13 | 2211b2329caa8 |
14 | c605384da741 |
15 | 5c461e3db187 |
hex | 2dc83eaa7495 |
50338068067477 has 2 divisors, whose sum is σ = 50338068067478. Its totient is φ = 50338068067476.
The previous prime is 50338068067411. The next prime is 50338068067489. The reversal of 50338068067477 is 77476086083305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25580268597636 + 24757799469841 = 5057694^2 + 4975721^2 .
It is a cyclic number.
It is not a de Polignac number, because 50338068067477 - 27 = 50338068067349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50338068067577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25169034033738 + 25169034033739.
It is an arithmetic number, because the mean of its divisors is an integer number (25169034033739).
Almost surely, 250338068067477 is an apocalyptic number.
It is an amenable number.
50338068067477 is a deficient number, since it is larger than the sum of its proper divisors (1).
50338068067477 is an equidigital number, since it uses as much as digits as its factorization.
50338068067477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 142248960, while the sum is 64.
The spelling of 50338068067477 in words is "fifty trillion, three hundred thirty-eight billion, sixty-eight million, sixty-seven thousand, four hundred seventy-seven".
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