Base | Representation |
---|---|
bin | 101110111000100111… |
… | …100010011000100101 |
3 | 11210221102101012111202 |
4 | 232320213202120211 |
5 | 1311100023344303 |
6 | 35043220012245 |
7 | 3431344021415 |
oct | 567047423045 |
9 | 153842335452 |
10 | 50342012453 |
11 | 1a393832077 |
12 | 990b531085 |
13 | 499388a365 |
14 | 2617d1c645 |
15 | 1499901c88 |
hex | bb89e2625 |
50342012453 has 2 divisors, whose sum is σ = 50342012454. Its totient is φ = 50342012452.
The previous prime is 50342012449. The next prime is 50342012489. The reversal of 50342012453 is 35421024305.
It is a happy number.
50342012453 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46553240644 + 3788771809 = 215762^2 + 61553^2 .
It is a cyclic number.
It is not a de Polignac number, because 50342012453 - 22 = 50342012449 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50342012353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25171006226 + 25171006227.
It is an arithmetic number, because the mean of its divisors is an integer number (25171006227).
Almost surely, 250342012453 is an apocalyptic number.
It is an amenable number.
50342012453 is a deficient number, since it is larger than the sum of its proper divisors (1).
50342012453 is an equidigital number, since it uses as much as digits as its factorization.
50342012453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 50342012453 its reverse (35421024305), we get a palindrome (85763036758).
The spelling of 50342012453 in words is "fifty billion, three hundred forty-two million, twelve thousand, four hundred fifty-three".
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