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503420605376471 is a prime number
BaseRepresentation
bin111001001110110111011111…
…0010110110010011111010111
32110000110112120120001212111222
41302131232332112302133113
51011441020344434021341
64542404122230120555
7211015636621060616
oct16235567626623727
92400415516055458
10503420605376471
111364505306501a2
12485663521b015b
13187b9489768683
148c45989d8387d
153d301d29d744b
hex1c9dbbe5b27d7

503420605376471 has 2 divisors, whose sum is σ = 503420605376472. Its totient is φ = 503420605376470.

The previous prime is 503420605376453. The next prime is 503420605376503. The reversal of 503420605376471 is 174673506024305.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 503420605376471 - 246 = 433051861198807 is a prime.

It is a super-3 number, since 3×5034206053764713 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (503420605370471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251710302688235 + 251710302688236.

It is an arithmetic number, because the mean of its divisors is an integer number (251710302688236).

Almost surely, 2503420605376471 is an apocalyptic number.

503420605376471 is a deficient number, since it is larger than the sum of its proper divisors (1).

503420605376471 is an equidigital number, since it uses as much as digits as its factorization.

503420605376471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12700800, while the sum is 53.

The spelling of 503420605376471 in words is "five hundred three trillion, four hundred twenty billion, six hundred five million, three hundred seventy-six thousand, four hundred seventy-one".