Base | Representation |
---|---|
bin | 111001001110110111011111… |
… | …0010110110010011111010111 |
3 | 2110000110112120120001212111222 |
4 | 1302131232332112302133113 |
5 | 1011441020344434021341 |
6 | 4542404122230120555 |
7 | 211015636621060616 |
oct | 16235567626623727 |
9 | 2400415516055458 |
10 | 503420605376471 |
11 | 1364505306501a2 |
12 | 485663521b015b |
13 | 187b9489768683 |
14 | 8c45989d8387d |
15 | 3d301d29d744b |
hex | 1c9dbbe5b27d7 |
503420605376471 has 2 divisors, whose sum is σ = 503420605376472. Its totient is φ = 503420605376470.
The previous prime is 503420605376453. The next prime is 503420605376503. The reversal of 503420605376471 is 174673506024305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 503420605376471 - 246 = 433051861198807 is a prime.
It is a super-3 number, since 3×5034206053764713 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (503420605370471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251710302688235 + 251710302688236.
It is an arithmetic number, because the mean of its divisors is an integer number (251710302688236).
Almost surely, 2503420605376471 is an apocalyptic number.
503420605376471 is a deficient number, since it is larger than the sum of its proper divisors (1).
503420605376471 is an equidigital number, since it uses as much as digits as its factorization.
503420605376471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12700800, while the sum is 53.
The spelling of 503420605376471 in words is "five hundred three trillion, four hundred twenty billion, six hundred five million, three hundred seventy-six thousand, four hundred seventy-one".
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