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5034511303 is a prime number
BaseRepresentation
bin1001011000001010…
…01000101111000111
3110222212022200011121
410230011020233013
540302313330203
62151323014411
7235521432343
oct45405105707
913885280147
105034511303
112153939948
12b8606a407
13623053093
1435a8c6623
151e6ec20bd
hex12c148bc7

5034511303 has 2 divisors, whose sum is σ = 5034511304. Its totient is φ = 5034511302.

The previous prime is 5034511283. The next prime is 5034511333. The reversal of 5034511303 is 3031154305.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5034511303 - 25 = 5034511271 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5034511333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517255651 + 2517255652.

It is an arithmetic number, because the mean of its divisors is an integer number (2517255652).

Almost surely, 25034511303 is an apocalyptic number.

5034511303 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034511303 is an equidigital number, since it uses as much as digits as its factorization.

5034511303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 5034511303 is about 70954.2902367433. The cubic root of 5034511303 is about 1713.9011627276.

Adding to 5034511303 its reverse (3031154305), we get a palindrome (8065665608).

The spelling of 5034511303 in words is "five billion, thirty-four million, five hundred eleven thousand, three hundred three".