Base | Representation |
---|---|
bin | 100100101000101100101… |
… | …1100111011001000110111 |
3 | 122211100201220200121210111 |
4 | 1021101121130323020313 |
5 | 1124444043310103044 |
6 | 14413050130403451 |
7 | 1026532003304026 |
oct | 111213134731067 |
9 | 18740656617714 |
10 | 5035202425399 |
11 | 1671465557813 |
12 | 693a33130587 |
13 | 2a6a82211193 |
14 | 1359c2b068bd |
15 | 8ae9ce39b34 |
hex | 4945973b237 |
5035202425399 has 2 divisors, whose sum is σ = 5035202425400. Its totient is φ = 5035202425398.
The previous prime is 5035202425397. The next prime is 5035202425417. The reversal of 5035202425399 is 9935242025305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5035202425399 - 21 = 5035202425397 is a prime.
Together with 5035202425397, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5035202425397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517601212699 + 2517601212700.
It is an arithmetic number, because the mean of its divisors is an integer number (2517601212700).
Almost surely, 25035202425399 is an apocalyptic number.
5035202425399 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035202425399 is an equidigital number, since it uses as much as digits as its factorization.
5035202425399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916000, while the sum is 49.
The spelling of 5035202425399 in words is "five trillion, thirty-five billion, two hundred two million, four hundred twenty-five thousand, three hundred ninety-nine".
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