Base | Representation |
---|---|
bin | 101110111001001111… |
… | …101011010010110101 |
3 | 11210222011011210022221 |
4 | 232321033223102311 |
5 | 1311110222102314 |
6 | 35044233322341 |
7 | 3431532324511 |
oct | 567117532265 |
9 | 153864153287 |
10 | 50352534709 |
11 | 1a399769654 |
12 | 9912b663b1 |
13 | 4995b02849 |
14 | 261949b141 |
15 | 149a7ce824 |
hex | bb93eb4b5 |
50352534709 has 2 divisors, whose sum is σ = 50352534710. Its totient is φ = 50352534708.
The previous prime is 50352534707. The next prime is 50352534737. The reversal of 50352534709 is 90743525305.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30512403684 + 19840131025 = 174678^2 + 140855^2 .
It is a cyclic number.
It is not a de Polignac number, because 50352534709 - 21 = 50352534707 is a prime.
Together with 50352534707, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50352534707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25176267354 + 25176267355.
It is an arithmetic number, because the mean of its divisors is an integer number (25176267355).
Almost surely, 250352534709 is an apocalyptic number.
It is an amenable number.
50352534709 is a deficient number, since it is larger than the sum of its proper divisors (1).
50352534709 is an equidigital number, since it uses as much as digits as its factorization.
50352534709 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 567000, while the sum is 43.
The spelling of 50352534709 in words is "fifty billion, three hundred fifty-two million, five hundred thirty-four thousand, seven hundred nine".
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