Base | Representation |
---|---|
bin | 100100101000101111110… |
… | …0101100011111101011011 |
3 | 122211101000002100212222202 |
4 | 1021101133211203331123 |
5 | 1124444301132244201 |
6 | 14413104244440415 |
7 | 1026534363211451 |
oct | 111213745437533 |
9 | 18741002325882 |
10 | 5035305353051 |
11 | 1671508668896 |
12 | 693a616a910b |
13 | 2a6a9a63b40c |
14 | 1359d265a9d1 |
15 | 8aea6ebbc6b |
hex | 4945f963f5b |
5035305353051 has 2 divisors, whose sum is σ = 5035305353052. Its totient is φ = 5035305353050.
The previous prime is 5035305353041. The next prime is 5035305353053. The reversal of 5035305353051 is 1503535035305.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5035305353051 is a prime.
Together with 5035305353053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5035305352996 and 5035305353014.
It is not a weakly prime, because it can be changed into another prime (5035305353053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517652676525 + 2517652676526.
It is an arithmetic number, because the mean of its divisors is an integer number (2517652676526).
Almost surely, 25035305353051 is an apocalyptic number.
5035305353051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035305353051 is an equidigital number, since it uses as much as digits as its factorization.
5035305353051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 253125, while the sum is 38.
The spelling of 5035305353051 in words is "five trillion, thirty-five billion, three hundred five million, three hundred fifty-three thousand, fifty-one".
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