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50353254443 is a prime number
BaseRepresentation
bin101110111001010010…
…011011000000101011
311210222012112100121202
4232321102123000223
51311110413120233
635044300554415
73431541413042
oct567122330053
9153865470552
1050353254443
111a39a110378
129913252a0b
134995cc531b
142619607559
15149a8c2be8
hexbb949b02b

50353254443 has 2 divisors, whose sum is σ = 50353254444. Its totient is φ = 50353254442.

The previous prime is 50353254409. The next prime is 50353254463. The reversal of 50353254443 is 34445235305.

50353254443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 50353254443 - 212 = 50353250347 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50353254397 and 50353254406.

It is not a weakly prime, because it can be changed into another prime (50353254463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25176627221 + 25176627222.

It is an arithmetic number, because the mean of its divisors is an integer number (25176627222).

Almost surely, 250353254443 is an apocalyptic number.

50353254443 is a deficient number, since it is larger than the sum of its proper divisors (1).

50353254443 is an equidigital number, since it uses as much as digits as its factorization.

50353254443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 38.

Adding to 50353254443 its reverse (34445235305), we get a palindrome (84798489748).

The spelling of 50353254443 in words is "fifty billion, three hundred fifty-three million, two hundred fifty-four thousand, four hundred forty-three".