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50353802537 is a prime number
BaseRepresentation
bin101110111001010100…
…100000110100101001
311210222020120012110112
4232321110200310221
51311111033140122
635044320424105
73431546155013
oct567124406451
9153866505415
1050353802537
111a39a455145
129913478035
13499615793c
14261970b1b3
15149a9802e2
hexbb9520d29

50353802537 has 2 divisors, whose sum is σ = 50353802538. Its totient is φ = 50353802536.

The previous prime is 50353802531. The next prime is 50353802539. The reversal of 50353802537 is 73520835305.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49739704576 + 614097961 = 223024^2 + 24781^2 .

It is a cyclic number.

It is not a de Polignac number, because 50353802537 - 216 = 50353737001 is a prime.

Together with 50353802539, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 50353802494 and 50353802503.

It is not a weakly prime, because it can be changed into another prime (50353802531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25176901268 + 25176901269.

It is an arithmetic number, because the mean of its divisors is an integer number (25176901269).

Almost surely, 250353802537 is an apocalyptic number.

It is an amenable number.

50353802537 is a deficient number, since it is larger than the sum of its proper divisors (1).

50353802537 is an equidigital number, since it uses as much as digits as its factorization.

50353802537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 378000, while the sum is 41.

The spelling of 50353802537 in words is "fifty billion, three hundred fifty-three million, eight hundred two thousand, five hundred thirty-seven".