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503550311350013 is a prime number
BaseRepresentation
bin111001001111110011111000…
…1011011110011111011111101
32110000220221100222202000122222
41302133213301123303323331
51012000132014201200023
64542543453003215125
7211031211064465154
oct16237476133637375
92400827328660588
10503550311350013
111364a0540255954
12485875105174a5
13187c878a754345
148c4bd7239259b
153d33774b1bcc8
hex1c9f9f16f3efd

503550311350013 has 2 divisors, whose sum is σ = 503550311350014. Its totient is φ = 503550311350012.

The previous prime is 503550311350003. The next prime is 503550311350061. The reversal of 503550311350013 is 310053113055305.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 503532147588484 + 18163761529 = 22439522^2 + 134773^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-503550311350013 is a prime.

It is a super-2 number, since 2×5035503113500132 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (503550311350003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251775155675006 + 251775155675007.

It is an arithmetic number, because the mean of its divisors is an integer number (251775155675007).

Almost surely, 2503550311350013 is an apocalyptic number.

It is an amenable number.

503550311350013 is a deficient number, since it is larger than the sum of its proper divisors (1).

503550311350013 is an equidigital number, since it uses as much as digits as its factorization.

503550311350013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50625, while the sum is 35.

The spelling of 503550311350013 in words is "five hundred three trillion, five hundred fifty billion, three hundred eleven million, three hundred fifty thousand, thirteen".