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5036532743351 is a prime number
BaseRepresentation
bin100100101001010100010…
…1111101011110010110111
3122211111011121220202221202
41021102220233223302313
51130004304340241401
614413430132003115
71026606655646024
oct111225057536267
918744147822852
105036532743351
111671a8848233a
1269414476049b
132a6c34a02a75
14135aab67a54b
158b029b1806b
hex494a8bebcb7

5036532743351 has 2 divisors, whose sum is σ = 5036532743352. Its totient is φ = 5036532743350.

The previous prime is 5036532743323. The next prime is 5036532743441. The reversal of 5036532743351 is 1533472356305.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5036532743351 - 218 = 5036532481207 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 5036532743296 and 5036532743305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5036532743551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2518266371675 + 2518266371676.

It is an arithmetic number, because the mean of its divisors is an integer number (2518266371676).

Almost surely, 25036532743351 is an apocalyptic number.

5036532743351 is a deficient number, since it is larger than the sum of its proper divisors (1).

5036532743351 is an equidigital number, since it uses as much as digits as its factorization.

5036532743351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402000, while the sum is 47.

The spelling of 5036532743351 in words is "five trillion, thirty-six billion, five hundred thirty-two million, seven hundred forty-three thousand, three hundred fifty-one".