Base | Representation |
---|---|
bin | 1001011000110100… |
… | …00111101000110111 |
3 | 111000020200010110212 |
4 | 10230122013220313 |
5 | 40310220334311 |
6 | 2152040540035 |
7 | 235616252021 |
oct | 45432075067 |
9 | 14006603425 |
10 | 5040011831 |
11 | 2156a56538 |
12 | b87a8161b |
13 | 62422a92a |
14 | 35b519011 |
15 | 1e770bc8b |
hex | 12c687a37 |
5040011831 has 2 divisors, whose sum is σ = 5040011832. Its totient is φ = 5040011830.
The previous prime is 5040011773. The next prime is 5040011833. The reversal of 5040011831 is 1381100405.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5040011831 is a prime.
It is a super-2 number, since 2×50400118312 = 50803438513239945122, which contains 22 as substring.
Together with 5040011833, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5040011797 and 5040011806.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5040011833) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520005915 + 2520005916.
It is an arithmetic number, because the mean of its divisors is an integer number (2520005916).
Almost surely, 25040011831 is an apocalyptic number.
5040011831 is a deficient number, since it is larger than the sum of its proper divisors (1).
5040011831 is an equidigital number, since it uses as much as digits as its factorization.
5040011831 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 23.
The square root of 5040011831 is about 70993.0407223131. The cubic root of 5040011831 is about 1714.5251180311.
The spelling of 5040011831 in words is "five billion, forty million, eleven thousand, eight hundred thirty-one".
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