5040031111 has 2 divisors, whose sum is σ = 5040031112. Its totient is φ = 5040031110.

The previous prime is 5040031103. The next prime is 5040031127. The reversal of 5040031111 is 1111300405.

It is an a-pointer prime, because the next prime (5040031127) can be obtained adding 5040031111 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5040031111 - 2³ = 5040031103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5040031211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520015555 + 2520015556.

It is an arithmetic number, because the mean of its divisors is an integer number (2520015556).

Almost surely, 2^5040031111 is an apocalyptic number.

5040031111 is a deficient number, since it is larger than the sum of its proper divisors (1).

5040031111 is an equidigital number, since it uses as much as digits as its factorization.

5040031111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 5040031111 is about 70993.1765101407. The cubic root of 5040031111 is about 1714.5273042695.

Adding to 5040031111 its reverse (1111300405), we get a palindrome (6151331516).

The spelling of 5040031111 in words is "five billion, forty million, thirty-one thousand, one hundred eleven".