Base | Representation |
---|---|
bin | 100100101011000101111… |
… | …0111110110100010001101 |
3 | 122211212000012011202011101 |
4 | 1021112023313312202031 |
5 | 1130040110342000100 |
6 | 14415300213423101 |
7 | 1030103256155113 |
oct | 111261367664215 |
9 | 18755005152141 |
10 | 5040343312525 |
11 | 1673663442364 |
12 | 694a2893aa91 |
13 | 2a73c12cab21 |
14 | 135d4d79dab3 |
15 | 8b19e42086a |
hex | 4958bdf688d |
5040343312525 has 24 divisors (see below), whose sum is σ = 6718952638080. Its totient is φ = 3738771999360.
The previous prime is 5040343312523. The next prime is 5040343312541. The reversal of 5040343312525 is 5252133430405.
It is not a de Polignac number, because 5040343312525 - 21 = 5040343312523 is a prime.
It is a super-3 number, since 3×50403433125253 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5040343312523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 112863304 + ... + 112907953.
It is an arithmetic number, because the mean of its divisors is an integer number (279956359920).
Almost surely, 25040343312525 is an apocalyptic number.
It is an amenable number.
5040343312525 is a deficient number, since it is larger than the sum of its proper divisors (1678609325555).
5040343312525 is a wasteful number, since it uses less digits than its factorization.
5040343312525 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 225771333 (or 225771328 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 37.
The spelling of 5040343312525 in words is "five trillion, forty billion, three hundred forty-three million, three hundred twelve thousand, five hundred twenty-five".
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