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5040417121 is a prime number
BaseRepresentation
bin1001011000110111…
…01010100101100001
3111000021102201102121
410230123222211201
540310321321441
62152053344241
7235622560435
oct45433524541
914007381377
105040417121
112157202a93
12b88038081
1362434024c
1435b5c29c5
151e778bdd1
hex12c6ea961

5040417121 has 2 divisors, whose sum is σ = 5040417122. Its totient is φ = 5040417120.

The previous prime is 5040417079. The next prime is 5040417149. The reversal of 5040417121 is 1217140405.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3147210000 + 1893207121 = 56100^2 + 43511^2 .

It is a cyclic number.

It is not a de Polignac number, because 5040417121 - 29 = 5040416609 is a prime.

It is not a weakly prime, because it can be changed into another prime (5040417191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520208560 + 2520208561.

It is an arithmetic number, because the mean of its divisors is an integer number (2520208561).

Almost surely, 25040417121 is an apocalyptic number.

It is an amenable number.

5040417121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5040417121 is an equidigital number, since it uses as much as digits as its factorization.

5040417121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1120, while the sum is 25.

The square root of 5040417121 is about 70995.8950996464. The cubic root of 5040417121 is about 1714.5710743558.

Adding to 5040417121 its reverse (1217140405), we get a palindrome (6257557526).

The spelling of 5040417121 in words is "five billion, forty million, four hundred seventeen thousand, one hundred twenty-one".