Base | Representation |
---|---|
bin | 10110111010111101010111… |
… | …01101110100110101100111 |
3 | 20121110121100212120212021112 |
4 | 23131132223231310311213 |
5 | 23101311022431313044 |
6 | 255111231555535235 |
7 | 13421410043030021 |
oct | 1335365355646547 |
9 | 217417325525245 |
10 | 50404322135399 |
11 | 15073397897811 |
12 | 57a08415ba51b |
13 | 2218151630b8b |
14 | c63821817011 |
15 | 5c61eac1109e |
hex | 2dd7abb74d67 |
50404322135399 has 2 divisors, whose sum is σ = 50404322135400. Its totient is φ = 50404322135398.
The previous prime is 50404322135369. The next prime is 50404322135443. The reversal of 50404322135399 is 99353122340405.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50404322135399 - 232 = 50400027168103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50404322135359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25202161067699 + 25202161067700.
It is an arithmetic number, because the mean of its divisors is an integer number (25202161067700).
Almost surely, 250404322135399 is an apocalyptic number.
50404322135399 is a deficient number, since it is larger than the sum of its proper divisors (1).
50404322135399 is an equidigital number, since it uses as much as digits as its factorization.
50404322135399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3499200, while the sum is 50.
The spelling of 50404322135399 in words is "fifty trillion, four hundred four billion, three hundred twenty-two million, one hundred thirty-five thousand, three hundred ninety-nine".
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