5040440413 has 2 divisors, whose sum is σ = 5040440414. Its totient is φ = 5040440412.

The previous prime is 5040440401. The next prime is 5040440429. The reversal of 5040440413 is 3140440405.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4986901924 + 53538489 = 70618^2 + 7317^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5040440413 is a prime.

It is a super-2 number, since 2×5040440413² = 50812079114007221138, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5040440813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520220206 + 2520220207.

It is an arithmetic number, because the mean of its divisors is an integer number (2520220207).

Almost surely, 2^5040440413 is an apocalyptic number.

It is an amenable number.

5040440413 is a deficient number, since it is larger than the sum of its proper divisors (1).

5040440413 is an equidigital number, since it uses as much as digits as its factorization.

5040440413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 25.

The square root of 5040440413 is about 70996.0591371099. The cubic root of 5040440413 is about 1714.5737153890.

Adding to 5040440413 its reverse (3140440405), we get a palindrome (8180880818).

The spelling of 5040440413 in words is "five billion, forty million, four hundred forty thousand, four hundred thirteen".