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50405543525021 is a prime number
BaseRepresentation
bin10110111010111111101001…
…00001000011101010011101
320121110201111222211212212012
423131133310201003222131
523101321023120300041
6255111553110321005
713421452233462506
oct1335376441035235
9217421458755765
1050405543525021
1115073964282923
1257a0b22659165
1322182b76a4129
14c638d9b13bad
155c626d0743eb
hex2dd7f4843a9d

50405543525021 has 2 divisors, whose sum is σ = 50405543525022. Its totient is φ = 50405543525020.

The previous prime is 50405543525011. The next prime is 50405543525023. The reversal of 50405543525021 is 12052534550405.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49817693167225 + 587850357796 = 7058165^2 + 766714^2 .

It is a cyclic number.

It is not a de Polignac number, because 50405543525021 - 230 = 50404469783197 is a prime.

Together with 50405543525023, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50405543525021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50405543525023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25202771762510 + 25202771762511.

It is an arithmetic number, because the mean of its divisors is an integer number (25202771762511).

Almost surely, 250405543525021 is an apocalyptic number.

It is an amenable number.

50405543525021 is a deficient number, since it is larger than the sum of its proper divisors (1).

50405543525021 is an equidigital number, since it uses as much as digits as its factorization.

50405543525021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600000, while the sum is 41.

The spelling of 50405543525021 in words is "fifty trillion, four hundred five billion, five hundred forty-three million, five hundred twenty-five thousand, twenty-one".