Search a number
-
+
504134055247997 is a prime number
BaseRepresentation
bin111001010100000011101101…
…1010010000100000001111101
32110002222202010002212112102202
41302220013123102010001331
51012034213021120413442
64544111553205001245
7211121324565654566
oct16250073322040175
92402882102775382
10504134055247997
111366a6063492399
12486606830b3225
131883b83955a675
148c6c30b67b16d
153d43a3c756c32
hex1ca81db48407d

504134055247997 has 2 divisors, whose sum is σ = 504134055247998. Its totient is φ = 504134055247996.

The previous prime is 504134055247843. The next prime is 504134055248003. The reversal of 504134055247997 is 799742550431405.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 495776804474116 + 8357250773881 = 22266046^2 + 2890891^2 .

It is a cyclic number.

It is not a de Polignac number, because 504134055247997 - 232 = 504129760280701 is a prime.

It is a super-2 number, since 2×5041340552479972 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (504134055244997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252067027623998 + 252067027623999.

It is an arithmetic number, because the mean of its divisors is an integer number (252067027623999).

Almost surely, 2504134055247997 is an apocalyptic number.

It is an amenable number.

504134055247997 is a deficient number, since it is larger than the sum of its proper divisors (1).

504134055247997 is an equidigital number, since it uses as much as digits as its factorization.

504134055247997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 190512000, while the sum is 65.

The spelling of 504134055247997 in words is "five hundred four trillion, one hundred thirty-four billion, fifty-five million, two hundred forty-seven thousand, nine hundred ninety-seven".