Base | Representation |
---|---|
bin | 10110111011011011001010… |
… | …10101000101100011100101 |
3 | 20121112010122212111012110011 |
4 | 23131231211111011203211 |
5 | 23102041304201124331 |
6 | 255122435321330221 |
7 | 13422514363065343 |
oct | 1335554525054345 |
9 | 217463585435404 |
10 | 50420321114341 |
11 | 1507a1578a5462 |
12 | 57a3967636971 |
13 | 221980111a419 |
14 | c644dc5a0993 |
15 | 5c68355a43b1 |
hex | 2ddb655458e5 |
50420321114341 has 2 divisors, whose sum is σ = 50420321114342. Its totient is φ = 50420321114340.
The previous prime is 50420321114321. The next prime is 50420321114347. The reversal of 50420321114341 is 14341112302405.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29402259088225 + 21018062026116 = 5422385^2 + 4584546^2 .
It is a cyclic number.
It is not a de Polignac number, because 50420321114341 - 217 = 50420320983269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50420321114347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25210160557170 + 25210160557171.
It is an arithmetic number, because the mean of its divisors is an integer number (25210160557171).
Almost surely, 250420321114341 is an apocalyptic number.
It is an amenable number.
50420321114341 is a deficient number, since it is larger than the sum of its proper divisors (1).
50420321114341 is an equidigital number, since it uses as much as digits as its factorization.
50420321114341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 50420321114341 its reverse (14341112302405), we get a palindrome (64761433416746).
The spelling of 50420321114341 in words is "fifty trillion, four hundred twenty billion, three hundred twenty-one million, one hundred fourteen thousand, three hundred forty-one".
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