Base | Representation |
---|---|
bin | 111001010100100111101100… |
… | …0000110010011001011111111 |
3 | 2110010021010112012122202122012 |
4 | 1302221033120012103023333 |
5 | 1012041444231134302111 |
6 | 4544211251221041435 |
7 | 211130031221050616 |
oct | 16251173006231377 |
9 | 2403233465582565 |
10 | 504211311244031 |
11 | 1367258a84876a6 |
12 | 48673643b5627b |
13 | 18845bcc03c8a1 |
14 | 8c71d59c0a87d |
15 | 3d45a5ed9c48b |
hex | 1ca93d81932ff |
504211311244031 has 2 divisors, whose sum is σ = 504211311244032. Its totient is φ = 504211311244030.
The previous prime is 504211311243953. The next prime is 504211311244093. The reversal of 504211311244031 is 130442113112405.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 504211311244031 - 218 = 504211310981887 is a prime.
It is a super-2 number, since 2×5042113112440312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (504211311244331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252105655622015 + 252105655622016.
It is an arithmetic number, because the mean of its divisors is an integer number (252105655622016).
Almost surely, 2504211311244031 is an apocalyptic number.
504211311244031 is a deficient number, since it is larger than the sum of its proper divisors (1).
504211311244031 is an equidigital number, since it uses as much as digits as its factorization.
504211311244031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 504211311244031 its reverse (130442113112405), we get a palindrome (634653424356436).
The spelling of 504211311244031 in words is "five hundred four trillion, two hundred eleven billion, three hundred eleven million, two hundred forty-four thousand, thirty-one".
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