Base | Representation |
---|---|
bin | 100100101011111010101… |
… | …0111010000100001110101 |
3 | 122212000120112102222001211 |
4 | 1021113311113100201311 |
5 | 1130102221431400031 |
6 | 14420151555321421 |
7 | 1030165156441231 |
oct | 111276527204165 |
9 | 18760515388054 |
10 | 5042113153141 |
11 | 1674391477859 |
12 | 6952415b0271 |
13 | 2a7613b8b4ac |
14 | 13607a8655c1 |
15 | 8b2549bcbb1 |
hex | 495f55d0875 |
5042113153141 has 2 divisors, whose sum is σ = 5042113153142. Its totient is φ = 5042113153140.
The previous prime is 5042113153111. The next prime is 5042113153151. The reversal of 5042113153141 is 1413513112405.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3326078652516 + 1716034500625 = 1823754^2 + 1309975^2 .
It is a cyclic number.
It is not a de Polignac number, because 5042113153141 - 211 = 5042113151093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5042113153111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2521056576570 + 2521056576571.
It is an arithmetic number, because the mean of its divisors is an integer number (2521056576571).
Almost surely, 25042113153141 is an apocalyptic number.
It is an amenable number.
5042113153141 is a deficient number, since it is larger than the sum of its proper divisors (1).
5042113153141 is an equidigital number, since it uses as much as digits as its factorization.
5042113153141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 5042113153141 its reverse (1413513112405), we get a palindrome (6455626265546).
The spelling of 5042113153141 in words is "five trillion, forty-two billion, one hundred thirteen million, one hundred fifty-three thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •