Base | Representation |
---|---|
bin | 100100101100000000111… |
… | …0001010001101001010111 |
3 | 122212001010001002220221210 |
4 | 1021120001301101221113 |
5 | 1130103133223100210 |
6 | 14420224352512503 |
7 | 1030203264606444 |
oct | 111300161215127 |
9 | 18761101086853 |
10 | 5042321300055 |
11 | 1674488a146a6 |
12 | 69529b24b733 |
13 | 2a7648038a50 |
14 | 13609a3689cb |
15 | 8b267dd5e20 |
hex | 49601c51a57 |
5042321300055 has 64 divisors (see below), whose sum is σ = 8779115842560. Its totient is φ = 2456435552256.
The previous prime is 5042321300053. The next prime is 5042321300101. The reversal of 5042321300055 is 5500031232405.
It is not a de Polignac number, because 5042321300055 - 21 = 5042321300053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5042321299995 and 5042321300031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5042321300053) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 179281224 + ... + 179309346.
It is an arithmetic number, because the mean of its divisors is an integer number (137173685040).
Almost surely, 25042321300055 is an apocalyptic number.
5042321300055 is a deficient number, since it is larger than the sum of its proper divisors (3736794542505).
5042321300055 is a wasteful number, since it uses less digits than its factorization.
5042321300055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37720.
The product of its (nonzero) digits is 18000, while the sum is 30.
The spelling of 5042321300055 in words is "five trillion, forty-two billion, three hundred twenty-one million, three hundred thousand, fifty-five".
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