50433021341 has 2 divisors, whose sum is σ = 50433021342. Its totient is φ = 50433021340.

The previous prime is 50433021319. The next prime is 50433021343. The reversal of 50433021341 is 14312033405.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50171520100 + 261501241 = 223990^2 + 16171^2 .

It is a cyclic number.

It is not a de Polignac number, because 50433021341 - 2¹⁰ = 50433020317 is a prime.

It is a super-2 number, since 2×50433021341² (a number of 22 digits) contains 22 as substring.

Together with 50433021343, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50433021341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50433021343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25216510670 + 25216510671.

It is an arithmetic number, because the mean of its divisors is an integer number (25216510671).

Almost surely, 2^50433021341 is an apocalyptic number.

It is an amenable number.

50433021341 is a deficient number, since it is larger than the sum of its proper divisors (1).

50433021341 is an equidigital number, since it uses as much as digits as its factorization.

50433021341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 50433021341 its reverse (14312033405), we get a palindrome (64745054746).

The spelling of 50433021341 in words is "fifty billion, four hundred thirty-three million, twenty-one thousand, three hundred forty-one".