Base | Representation |
---|---|
bin | 101110111110101001… |
… | …001111110100110111 |
3 | 11211012110122012111201 |
4 | 232332221033310313 |
5 | 1311301414432043 |
6 | 35101231113331 |
7 | 3434012323345 |
oct | 567651176467 |
9 | 154173565451 |
10 | 50443124023 |
11 | 1a435912756 |
12 | 9939372847 |
13 | 49ab7ccaa6 |
14 | 262751c995 |
15 | 14a3725c4d |
hex | bbea4fd37 |
50443124023 has 2 divisors, whose sum is σ = 50443124024. Its totient is φ = 50443124022.
The previous prime is 50443124009. The next prime is 50443124029. The reversal of 50443124023 is 32042134405.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50443124023 - 221 = 50441026871 is a prime.
It is a super-2 number, since 2×504431240232 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50443123982 and 50443124000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50443124029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25221562011 + 25221562012.
It is an arithmetic number, because the mean of its divisors is an integer number (25221562012).
Almost surely, 250443124023 is an apocalyptic number.
50443124023 is a deficient number, since it is larger than the sum of its proper divisors (1).
50443124023 is an equidigital number, since it uses as much as digits as its factorization.
50443124023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 28.
Adding to 50443124023 its reverse (32042134405), we get a palindrome (82485258428).
The spelling of 50443124023 in words is "fifty billion, four hundred forty-three million, one hundred twenty-four thousand, twenty-three".
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