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50490983 is a prime number
BaseRepresentation
bin1100000010011…
…0111001100111
310112000012121102
43000212321213
5100411202413
65002110315
71152111014
oct300467147
9115005542
1050490983
1126556694
1214aab39b
13a5caa2a
1469c470b
154675458
hex3026e67

50490983 has 2 divisors, whose sum is σ = 50490984. Its totient is φ = 50490982.

The previous prime is 50490949. The next prime is 50490997. The reversal of 50490983 is 38909405.

50490983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50490983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50490283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25245491 + 25245492.

It is an arithmetic number, because the mean of its divisors is an integer number (25245492).

Almost surely, 250490983 is an apocalyptic number.

50490983 is a deficient number, since it is larger than the sum of its proper divisors (1).

50490983 is an equidigital number, since it uses as much as digits as its factorization.

50490983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 38.

The square root of 50490983 is about 7105.7007395471. The cubic root of 50490983 is about 369.6050887550.

The spelling of 50490983 in words is "fifty million, four hundred ninety thousand, nine hundred eighty-three".