Base | Representation |
---|---|
bin | 100100101111010010000… |
… | …0001101101011010001111 |
3 | 122212201020002011211012001 |
4 | 1021132210001231122033 |
5 | 1130212021122444432 |
6 | 14423344543253131 |
7 | 1030542212646652 |
oct | 111364401553217 |
9 | 18781202154161 |
10 | 5049338484367 |
11 | 1677459a36081 |
12 | 6967192aa1a7 |
13 | 2a81c5a7a608 |
14 | 1365642b9899 |
15 | 8b528e969e7 |
hex | 497a406d68f |
5049338484367 has 2 divisors, whose sum is σ = 5049338484368. Its totient is φ = 5049338484366.
The previous prime is 5049338484317. The next prime is 5049338484397. The reversal of 5049338484367 is 7634848339405.
5049338484367 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5049338484367 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5049338484299 and 5049338484308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5049338484317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2524669242183 + 2524669242184.
It is an arithmetic number, because the mean of its divisors is an integer number (2524669242184).
Almost surely, 25049338484367 is an apocalyptic number.
5049338484367 is a deficient number, since it is larger than the sum of its proper divisors (1).
5049338484367 is an equidigital number, since it uses as much as digits as its factorization.
5049338484367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 209018880, while the sum is 64.
The spelling of 5049338484367 in words is "five trillion, forty-nine billion, three hundred thirty-eight million, four hundred eighty-four thousand, three hundred sixty-seven".
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