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505013272774343 is a prime number
BaseRepresentation
bin111001011010011101001000…
…0101110110000011011000111
32110020002210112021202120100122
41302310322100232300123013
51012143114140312234333
64550023521131532155
7211242001453432124
oct16264722056603307
92406083467676318
10505013272774343
11136a04a208a3123
1248782b572ba05b
13188a37164b4488
148c9cab689574b
153d5b84a4a3798
hex1cb4e90bb06c7

505013272774343 has 2 divisors, whose sum is σ = 505013272774344. Its totient is φ = 505013272774342.

The previous prime is 505013272774331. The next prime is 505013272774357. The reversal of 505013272774343 is 343477272310505.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 505013272774343 - 212 = 505013272770247 is a prime.

It is a super-3 number, since 3×5050132727743433 (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (505013272674343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252506636387171 + 252506636387172.

It is an arithmetic number, because the mean of its divisors is an integer number (252506636387172).

Almost surely, 2505013272774343 is an apocalyptic number.

505013272774343 is a deficient number, since it is larger than the sum of its proper divisors (1).

505013272774343 is an equidigital number, since it uses as much as digits as its factorization.

505013272774343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14817600, while the sum is 53.

The spelling of 505013272774343 in words is "five hundred five trillion, thirteen billion, two hundred seventy-two million, seven hundred seventy-four thousand, three hundred forty-three".