Base | Representation |
---|---|
bin | 100100101111101101001… |
… | …1100000101100000010111 |
3 | 122212210120200221010202102 |
4 | 1021133122130011200113 |
5 | 1130220403322242341 |
6 | 14424015313432315 |
7 | 1030603636226441 |
oct | 111373234054027 |
9 | 18783520833672 |
10 | 5050251368471 |
11 | 1677888268451 |
12 | 696932b6b69b |
13 | 2a830cc3551a |
14 | 13660d62b491 |
15 | 8b57e1bac9b |
hex | 497da705817 |
5050251368471 has 2 divisors, whose sum is σ = 5050251368472. Its totient is φ = 5050251368470.
The previous prime is 5050251368443. The next prime is 5050251368543. The reversal of 5050251368471 is 1748631520505.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5050251368471 is a prime.
It is a super-3 number, since 3×50502513684713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5050251368401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2525125684235 + 2525125684236.
It is an arithmetic number, because the mean of its divisors is an integer number (2525125684236).
Almost surely, 25050251368471 is an apocalyptic number.
5050251368471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5050251368471 is an equidigital number, since it uses as much as digits as its factorization.
5050251368471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008000, while the sum is 47.
Adding to 5050251368471 its reverse (1748631520505), we get a palindrome (6798882888976).
The spelling of 5050251368471 in words is "five trillion, fifty billion, two hundred fifty-one million, three hundred sixty-eight thousand, four hundred seventy-one".
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