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5052430314299 is a prime number
BaseRepresentation
bin100100110000101110001…
…0100000110101100111011
3122220000012120000001111202
41021201130110012230323
51130234334130024144
614425015432044415
71031011635036254
oct111413424065473
918800176001452
105052430314299
1116787a6217725
1269724083370b
132a85994a4994
14136778b87b2b
158b65a62964e
hex4985c506b3b

5052430314299 has 2 divisors, whose sum is σ = 5052430314300. Its totient is φ = 5052430314298.

The previous prime is 5052430314289. The next prime is 5052430314301. The reversal of 5052430314299 is 9924130342505.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5052430314299 is a prime.

It is a super-2 number, since 2×50524303142992 (a number of 26 digits) contains 22 as substring.

Together with 5052430314301, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5052430314229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526215157149 + 2526215157150.

It is an arithmetic number, because the mean of its divisors is an integer number (2526215157150).

Almost surely, 25052430314299 is an apocalyptic number.

5052430314299 is a deficient number, since it is larger than the sum of its proper divisors (1).

5052430314299 is an equidigital number, since it uses as much as digits as its factorization.

5052430314299 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 47.

The spelling of 5052430314299 in words is "five trillion, fifty-two billion, four hundred thirty million, three hundred fourteen thousand, two hundred ninety-nine".