Base | Representation |
---|---|
bin | 100100110000101110001… |
… | …0100000110101100111011 |
3 | 122220000012120000001111202 |
4 | 1021201130110012230323 |
5 | 1130234334130024144 |
6 | 14425015432044415 |
7 | 1031011635036254 |
oct | 111413424065473 |
9 | 18800176001452 |
10 | 5052430314299 |
11 | 16787a6217725 |
12 | 69724083370b |
13 | 2a85994a4994 |
14 | 136778b87b2b |
15 | 8b65a62964e |
hex | 4985c506b3b |
5052430314299 has 2 divisors, whose sum is σ = 5052430314300. Its totient is φ = 5052430314298.
The previous prime is 5052430314289. The next prime is 5052430314301. The reversal of 5052430314299 is 9924130342505.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5052430314299 is a prime.
It is a super-2 number, since 2×50524303142992 (a number of 26 digits) contains 22 as substring.
Together with 5052430314301, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5052430314229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526215157149 + 2526215157150.
It is an arithmetic number, because the mean of its divisors is an integer number (2526215157150).
Almost surely, 25052430314299 is an apocalyptic number.
5052430314299 is a deficient number, since it is larger than the sum of its proper divisors (1).
5052430314299 is an equidigital number, since it uses as much as digits as its factorization.
5052430314299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 47.
The spelling of 5052430314299 in words is "five trillion, fifty-two billion, four hundred thirty million, three hundred fourteen thousand, two hundred ninety-nine".
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