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5053314241333 is a prime number
BaseRepresentation
bin100100110001001000100…
…0000000001001100110101
3122220002111011021012110001
41021202101000001030311
51130243141421210313
614425243245431301
71031042560223101
oct111422100011465
918802434235401
105053314241333
11167910a171136
1269744886b531
132a86aa661527
1413682031c901
158b6ad02dadd
hex49891001335

5053314241333 has 2 divisors, whose sum is σ = 5053314241334. Its totient is φ = 5053314241332.

The previous prime is 5053314241289. The next prime is 5053314241357. The reversal of 5053314241333 is 3331424133505.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2618160233329 + 2435154008004 = 1618073^2 + 1560498^2 .

It is a cyclic number.

It is not a de Polignac number, because 5053314241333 - 237 = 4915875287861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5053314241292 and 5053314241301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5053314241373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526657120666 + 2526657120667.

It is an arithmetic number, because the mean of its divisors is an integer number (2526657120667).

Almost surely, 25053314241333 is an apocalyptic number.

It is an amenable number.

5053314241333 is a deficient number, since it is larger than the sum of its proper divisors (1).

5053314241333 is an equidigital number, since it uses as much as digits as its factorization.

5053314241333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 37.

Adding to 5053314241333 its reverse (3331424133505), we get a palindrome (8384738374838).

The spelling of 5053314241333 in words is "five trillion, fifty-three billion, three hundred fourteen million, two hundred forty-one thousand, three hundred thirty-three".