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5054125441613 is a prime number
BaseRepresentation
bin100100110001100000101…
…0110100000001001001101
3122220011120200200110000212
41021203001112200021031
51130301322103112423
614425455544332205
71031101640265353
oct111430126401115
918804520613025
105054125441613
111679496061996
12697634474065
132a87a97363b1
14136899d617d3
158b709369578
hex498c15a024d

5054125441613 has 2 divisors, whose sum is σ = 5054125441614. Its totient is φ = 5054125441612.

The previous prime is 5054125441583. The next prime is 5054125441669. The reversal of 5054125441613 is 3161445214505.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3617919738889 + 1436205702724 = 1902083^2 + 1198418^2 .

It is a cyclic number.

It is not a de Polignac number, because 5054125441613 - 210 = 5054125440589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5054125401613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527062720806 + 2527062720807.

It is an arithmetic number, because the mean of its divisors is an integer number (2527062720807).

Almost surely, 25054125441613 is an apocalyptic number.

It is an amenable number.

5054125441613 is a deficient number, since it is larger than the sum of its proper divisors (1).

5054125441613 is an equidigital number, since it uses as much as digits as its factorization.

5054125441613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 41.

The spelling of 5054125441613 in words is "five trillion, fifty-four billion, one hundred twenty-five million, four hundred forty-one thousand, six hundred thirteen".