Base | Representation |
---|---|
bin | 100100110001100000101… |
… | …0110100000001001001101 |
3 | 122220011120200200110000212 |
4 | 1021203001112200021031 |
5 | 1130301322103112423 |
6 | 14425455544332205 |
7 | 1031101640265353 |
oct | 111430126401115 |
9 | 18804520613025 |
10 | 5054125441613 |
11 | 1679496061996 |
12 | 697634474065 |
13 | 2a87a97363b1 |
14 | 136899d617d3 |
15 | 8b709369578 |
hex | 498c15a024d |
5054125441613 has 2 divisors, whose sum is σ = 5054125441614. Its totient is φ = 5054125441612.
The previous prime is 5054125441583. The next prime is 5054125441669. The reversal of 5054125441613 is 3161445214505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3617919738889 + 1436205702724 = 1902083^2 + 1198418^2 .
It is a cyclic number.
It is not a de Polignac number, because 5054125441613 - 210 = 5054125440589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5054125401613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527062720806 + 2527062720807.
It is an arithmetic number, because the mean of its divisors is an integer number (2527062720807).
Almost surely, 25054125441613 is an apocalyptic number.
It is an amenable number.
5054125441613 is a deficient number, since it is larger than the sum of its proper divisors (1).
5054125441613 is an equidigital number, since it uses as much as digits as its factorization.
5054125441613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288000, while the sum is 41.
The spelling of 5054125441613 in words is "five trillion, fifty-four billion, one hundred twenty-five million, four hundred forty-one thousand, six hundred thirteen".
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