Base | Representation |
---|---|
bin | 100100110001100000101… |
… | …0110100000001000101111 |
3 | 122220011120200200102222202 |
4 | 1021203001112200020233 |
5 | 1130301322103112313 |
6 | 14425455544332115 |
7 | 1031101640265311 |
oct | 111430126401057 |
9 | 18804520612882 |
10 | 5054125441583 |
11 | 1679496061969 |
12 | 69763447403b |
13 | 2a87a973638a |
14 | 136899d617b1 |
15 | 8b709369558 |
hex | 498c15a022f |
5054125441583 has 2 divisors, whose sum is σ = 5054125441584. Its totient is φ = 5054125441582.
The previous prime is 5054125441489. The next prime is 5054125441613. The reversal of 5054125441583 is 3851445214505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5054125441583 - 28 = 5054125441327 is a prime.
It is a super-3 number, since 3×50541254415833 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5054025441583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527062720791 + 2527062720792.
It is an arithmetic number, because the mean of its divisors is an integer number (2527062720792).
Almost surely, 25054125441583 is an apocalyptic number.
5054125441583 is a deficient number, since it is larger than the sum of its proper divisors (1).
5054125441583 is an equidigital number, since it uses as much as digits as its factorization.
5054125441583 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1920000, while the sum is 47.
The spelling of 5054125441583 in words is "five trillion, fifty-four billion, one hundred twenty-five million, four hundred forty-one thousand, five hundred eighty-three".
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