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5054321414143 is a prime number
BaseRepresentation
bin100100110001100110100…
…0010000100111111111111
3122220012002100102212210201
41021203031002010333333
51130302222240223033
614425531224544331
71031106540110011
oct111431502047777
918805070385721
105054321414143
111679586743a61
1269768a0220a7
132a880b210481
141368b7db61b1
158b71b67a47d
hex498cd084fff

5054321414143 has 2 divisors, whose sum is σ = 5054321414144. Its totient is φ = 5054321414142.

The previous prime is 5054321414117. The next prime is 5054321414183. The reversal of 5054321414143 is 3414141234505.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5054321414143 - 25 = 5054321414111 is a prime.

It is an alternating number because its digits alternate between odd and even.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5054321414183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527160707071 + 2527160707072.

It is an arithmetic number, because the mean of its divisors is an integer number (2527160707072).

Almost surely, 25054321414143 is an apocalyptic number.

5054321414143 is a deficient number, since it is larger than the sum of its proper divisors (1).

5054321414143 is an equidigital number, since it uses as much as digits as its factorization.

5054321414143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 5054321414143 its reverse (3414141234505), we get a palindrome (8468462648648).

The spelling of 5054321414143 in words is "five trillion, fifty-four billion, three hundred twenty-one million, four hundred fourteen thousand, one hundred forty-three".