Base | Representation |
---|---|
bin | 10110111111001101101111… |
… | …00101000101110100101011 |
3 | 20121222120210202020002221002 |
4 | 23133212313211011310223 |
5 | 23111210011303412311 |
6 | 255302334015505215 |
7 | 13435104516625616 |
oct | 1337466745056453 |
9 | 217876722202832 |
10 | 50550550060331 |
11 | 1511a405728052 |
12 | 5805050b2820b |
13 | 2228b86572549 |
14 | c6a93422517d |
15 | 5c9e0858d93b |
hex | 2df9b7945d2b |
50550550060331 has 2 divisors, whose sum is σ = 50550550060332. Its totient is φ = 50550550060330.
The previous prime is 50550550060277. The next prime is 50550550060333. The reversal of 50550550060331 is 13306005505505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50550550060331 - 210 = 50550550059307 is a prime.
It is a super-2 number, since 2×505505500603312 (a number of 28 digits) contains 22 as substring.
Together with 50550550060333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (50550550060333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25275275030165 + 25275275030166.
It is an arithmetic number, because the mean of its divisors is an integer number (25275275030166).
Almost surely, 250550550060331 is an apocalyptic number.
50550550060331 is a deficient number, since it is larger than the sum of its proper divisors (1).
50550550060331 is an equidigital number, since it uses as much as digits as its factorization.
50550550060331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168750, while the sum is 38.
Adding to 50550550060331 its reverse (13306005505505), we get a palindrome (63856555565836).
The spelling of 50550550060331 in words is "fifty trillion, five hundred fifty billion, five hundred fifty million, sixty thousand, three hundred thirty-one".
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