Base | Representation |
---|---|
bin | 100100110010000001010… |
… | …1110000000111001001111 |
3 | 122220021102010021200121011 |
4 | 1021210002232000321033 |
5 | 1130311043330432421 |
6 | 14430200442150051 |
7 | 1031141055033415 |
oct | 111440256007117 |
9 | 18807363250534 |
10 | 5055222124111 |
11 | 16799a9110765 |
12 | 69789b7b2327 |
13 | 2a89229c5053 |
14 | 1369618792b5 |
15 | 8b7707974e1 |
hex | 49902b80e4f |
5055222124111 has 2 divisors, whose sum is σ = 5055222124112. Its totient is φ = 5055222124110.
The previous prime is 5055222124109. The next prime is 5055222124177. The reversal of 5055222124111 is 1114212225505.
5055222124111 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5055222124111 - 21 = 5055222124109 is a prime.
Together with 5055222124109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5055202124111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527611062055 + 2527611062056.
It is an arithmetic number, because the mean of its divisors is an integer number (2527611062056).
Almost surely, 25055222124111 is an apocalyptic number.
5055222124111 is a deficient number, since it is larger than the sum of its proper divisors (1).
5055222124111 is an equidigital number, since it uses as much as digits as its factorization.
5055222124111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8000, while the sum is 31.
Adding to 5055222124111 its reverse (1114212225505), we get a palindrome (6169434349616).
The spelling of 5055222124111 in words is "five trillion, fifty-five billion, two hundred twenty-two million, one hundred twenty-four thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •