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50555550050561 is a prime number
BaseRepresentation
bin10110111111010111000011…
…00110100010100100000001
320122000001201012120221002102
423133223201212202210001
523111300231303104221
6255304522111000145
713435342442062613
oct1337534146424401
9218001635527072
1050555550050561
1115121541028786
125806007509055
1322294a23c984a
14c6ac8a2c2db3
155ca0ec4e230b
hex2dfae19a2901

50555550050561 has 2 divisors, whose sum is σ = 50555550050562. Its totient is φ = 50555550050560.

The previous prime is 50555550050539. The next prime is 50555550050563. The reversal of 50555550050561 is 16505005555505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46612025290000 + 3943524760561 = 6827300^2 + 1985831^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50555550050561 is a prime.

Together with 50555550050563, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (50555550050563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25277775025280 + 25277775025281.

It is an arithmetic number, because the mean of its divisors is an integer number (25277775025281).

Almost surely, 250555550050561 is an apocalyptic number.

It is an amenable number.

50555550050561 is a deficient number, since it is larger than the sum of its proper divisors (1).

50555550050561 is an equidigital number, since it uses as much as digits as its factorization.

50555550050561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2343750, while the sum is 47.

The spelling of 50555550050561 in words is "fifty trillion, five hundred fifty-five billion, five hundred fifty million, fifty thousand, five hundred sixty-one".