Base | Representation |
---|---|
bin | 100100110010011011100… |
… | …0010111010001000111111 |
3 | 122220100200022012020211121 |
4 | 1021210313002322020333 |
5 | 1130314343101013303 |
6 | 14430423522331411 |
7 | 1031201605015141 |
oct | 111446702721077 |
9 | 18810608166747 |
10 | 5056100016703 |
11 | 167a30971342a |
12 | 697aa57b9b67 |
13 | 2a8a3284b018 |
14 | 136a062bcc91 |
15 | 8b7c28a89bd |
hex | 499370ba23f |
5056100016703 has 2 divisors, whose sum is σ = 5056100016704. Its totient is φ = 5056100016702.
The previous prime is 5056100016589. The next prime is 5056100016733. The reversal of 5056100016703 is 3076100016505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5056100016703 - 213 = 5056100008511 is a prime.
It is a super-3 number, since 3×50561000167033 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5056100016733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2528050008351 + 2528050008352.
It is an arithmetic number, because the mean of its divisors is an integer number (2528050008352).
Almost surely, 25056100016703 is an apocalyptic number.
5056100016703 is a deficient number, since it is larger than the sum of its proper divisors (1).
5056100016703 is an equidigital number, since it uses as much as digits as its factorization.
5056100016703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 34.
The spelling of 5056100016703 in words is "five trillion, fifty-six billion, one hundred million, sixteen thousand, seven hundred three".
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