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5058417143333 is a prime number
BaseRepresentation
bin100100110011100000100…
…1010000010111000100101
3122220120122210021111000102
41021213001022002320211
51130334114242041313
614431445454353445
71031313202200311
oct111470112027045
918816583244012
105058417143333
111680298671a14
126984317bb885
132a901190b778
14136b85d28b41
158b8ab00ea58
hex499c1282e25

5058417143333 has 2 divisors, whose sum is σ = 5058417143334. Its totient is φ = 5058417143332.

The previous prime is 5058417143317. The next prime is 5058417143341. The reversal of 5058417143333 is 3333417148505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3333757436164 + 1724659707169 = 1825858^2 + 1313263^2 .

It is a cyclic number.

It is not a de Polignac number, because 5058417143333 - 24 = 5058417143317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5058417113333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2529208571666 + 2529208571667.

It is an arithmetic number, because the mean of its divisors is an integer number (2529208571667).

Almost surely, 25058417143333 is an apocalyptic number.

It is an amenable number.

5058417143333 is a deficient number, since it is larger than the sum of its proper divisors (1).

5058417143333 is an equidigital number, since it uses as much as digits as its factorization.

5058417143333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1814400, while the sum is 47.

The spelling of 5058417143333 in words is "five trillion, fifty-eight billion, four hundred seventeen million, one hundred forty-three thousand, three hundred thirty-three".