Base | Representation |
---|---|
bin | 100100111111111111101… |
… | …1011000000000000001111 |
3 | 200000010212112100221211221 |
4 | 1021333333123000000033 |
5 | 1131304023241013101 |
6 | 14452042333024211 |
7 | 1033252531142113 |
oct | 111777733000017 |
9 | 20003775327757 |
10 | 5085231579151 |
11 | 16906a8722479 |
12 | 6a1675925067 |
13 | 2ab6c601a939 |
14 | 1381ab265743 |
15 | 8c42a13caa1 |
hex | 49fff6c000f |
5085231579151 has 2 divisors, whose sum is σ = 5085231579152. Its totient is φ = 5085231579150.
The previous prime is 5085231579101. The next prime is 5085231579157. The reversal of 5085231579151 is 1519751325805.
It is a happy number.
5085231579151 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5085231579151 - 215 = 5085231546383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5085231579157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2542615789575 + 2542615789576.
It is an arithmetic number, because the mean of its divisors is an integer number (2542615789576).
Almost surely, 25085231579151 is an apocalyptic number.
5085231579151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5085231579151 is an equidigital number, since it uses as much as digits as its factorization.
5085231579151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1890000, while the sum is 52.
The spelling of 5085231579151 in words is "five trillion, eighty-five billion, two hundred thirty-one million, five hundred seventy-nine thousand, one hundred fifty-one".
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