50934973 has 2 divisors, whose sum is σ = 50934974. Its totient is φ = 50934972.

The previous prime is 50934971. The next prime is 50935019. The reversal of 50934973 is 37943905.

50934973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42484324 + 8450649 = 6518^2 + 2907^2 .

It is a cyclic number.

It is not a de Polignac number, because 50934973 - 2¹ = 50934971 is a prime.

It is a super-4 number, since 4×50934973⁴ (a number of 32 digits) contains 4444 as substring.

Together with 50934971, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50934971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25467486 + 25467487.

It is an arithmetic number, because the mean of its divisors is an integer number (25467487).

Almost surely, 2^50934973 is an apocalyptic number.

It is an amenable number.

50934973 is a deficient number, since it is larger than the sum of its proper divisors (1).

50934973 is an equidigital number, since it uses as much as digits as its factorization.

50934973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 102060, while the sum is 40.

The square root of 50934973 is about 7136.8741757159. The cubic root of 50934973 is about 370.6852967787.

The spelling of 50934973 in words is "fifty million, nine hundred thirty-four thousand, nine hundred seventy-three".